Q41.Molal depression constant for a solvent is 4.0 K kg mol−1. The depression in the freezing point of the solvent for 0.03 mol kg−1 solution of K2SO4 is: (Assume complete dissociation of the electrolyte) (1) 0.36 K (2) 0.24 K (3) 0.18 K (4) 0.12 K
What This Question Tests
This question requires calculating the depression in freezing point for an electrolyte solution, correctly incorporating the van't Hoff factor due to complete dissociation.
Concepts Tested
Formulas Used
ΔTf = i * Kf * m
📚 NCERT Sections This Tests
1.32 — Calculate The Depression In The Freezing Point Of Water When 10 G Of
Chemistry Class 11 · Chapter 1
1.32 Calculate the depression in the freezing point of water when 10 g of CH3CH2CHClCOOH is added to 250 g of water. Ka = 1.4 × 10–3, Kf = 1.86 K kg mol–1. 1.33 19.5 g of CH2FCOOH is dissolved in 500 g of water. The depression in the freezing point of water observed is 1.00 C. Calculate the van’t Hoff factor and dissociation constant of fluoroacetic acid.
2.8 — The Conductivity Of 0.20 M Solution Of Kcl At 298 K Is 0.0248 S Cm–1. Calculate
Chemistry Class 11 · Chapter 2
2.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.
1.35 — Henry’S Law Constant For The Molality Of Methane In Benzene At 298 K Is
Chemistry Class 11 · Chapter 1
1.35 Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.
📋 Question Details
- Chapter
- Solutions
- Topic
- Colligative properties
- Year
- 2019
- Shift
- 09 Apr Shift 2
- Q Number
- Q41
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 2: Solutions
More from this Chapter
Q81.The orbital angular momentum for an electron revolving in an orbit is given by √l(l + 1) ⋅ 2πh . This momentum for an s-electron will be given by (1) zero (2) h 2π (3) √2 ⋅ 2πh (4) + 21 ⋅ 2πh JEE Main 2003 JEE Main Previous Year Paper
Q90.Which one of the following aqueous solutions will exhibit highest boiling point? (1) 0.01MNa2SO4 (2) 0.015M glucose (3) 0.015M urea (4) 0.01MKNO3
Q79.Two solutions of a substance (non electrolyte) are mixed in the following manner. 480 ml of 1.5 M first solution + 520 mL of 1.2 M second solution. What is the molarity of the final mixture? (1) 1.20 M (2) 1.50 M (3) 1.344 M (4) 2.70 M
Q92.Benzene and toluene form nearly ideal solutions. At 20∘C, the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20∘C for a solution containing 78 g of benzene and 46 g of toluene in torr is (1) 50 (2) 25 (3) 37.5 (4) 53.5