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MathsHardMulti concept2024 · 06 Apr Shift 2

Q83.The length of the latus rectum and directrices of a hyperbola with eccentricity e are 9 and x = ± 4 , √13 respectively. Let the line y −√3x + √3 = 0 touch this hyperbola at (x0, y0). If m is the product of the focal distances of the point (x0, y0), then 4e2 + m is equal to ________

What This Question Tests

This multi-concept question integrates several hyperbola properties including latus rectum, directrices, eccentricity, and tangent conditions. It requires careful algebraic manipulation to combine these concepts.

Concepts Tested

Equation of hyperbolaLatus RectumDirectricesEccentricityTangent conditionFocal distance property

Formulas Used

Latus Rectum = 2b²/a

Directrices x = ±a/e

b² = a²(e²-1)

Tangent y = mx + c to x²/a² - y²/b² = 1 implies c² = a²m² - b²

Product of focal distances = |e²x₀² - a²|

📚 NCERT Sections This Tests

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