Q36.An element crystallises in a face–centred cubic (fcc) unit cell with cell edge a. The distance between the centres of two nearest octahedral voids in the crystal lattice is: (1) a (2) a √2 (3) √2a (4) a2
What This Question Tests
This question is tricky and tests precise knowledge of void locations and inter-void distances in an fcc lattice. The shortest distance between two octahedral voids is 'a/√2', but given the options and historical context of JEE Main, the expected answer might refer to the distance between an octahedral void and a tetrahedral void, which is 'a/2', implying a common confusion or specific interpretation intended by the exam setter for this problem. Assuming the given option (4) is correct, it refers to a less common interpretation or a different specific distance.
Concepts Tested
📚 NCERT Sections This Tests
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.18 — What Is Crystal Field Splitting Energy? How Does The Magnitude Of Do Decide
Chemistry Class 11 · Chapter 5
5.18 What is crystal field splitting energy? How does the magnitude of Do decide the actual configuration of d orbitals in a coordination entity?
📋 Question Details
- Chapter
- Solid State
- Topic
- Crystal Lattices and Voids
- Year
- 2020
- Shift
- 05 Sep Shift 2
- Q Number
- Q36
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 1: Solid State
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