Q83.The term independent of x in the expansion of 10 [ x2/3−x1/3+1x+1 − x−x1/2x−1 ] , x ≠1 , is equal to ___.
What This Question Tests
The core of this problem is to first simplify the base of the binomial expansion using algebraic identities. Once simplified to a form (x^a + x^b)^n, the general term is used to find the power of x and set it to zero for the term independent of x.
Concepts Tested
Formulas Used
a^3+b^3 = (a+b)(a^2-ab+b^2)
a^2-b^2 = (a-b)(a+b)
T_{r+1} = nCr * (ax^p)^n-r * (bx^q)^r
📚 NCERT Sections This Tests
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
8.17 — Complete Each Synthesis By Giving Missing Starting Material, Reagent Or Products
Chemistry Class 12 · Chapter 8
8.17 Complete each synthesis by giving missing starting material, reagent or products
13.2 — Obtain The Binding Energy Of The Nuclei 5626Fe And 20983 Bi In Units Of
Physics Class 12 · Chapter 13
13.2 Obtain the binding energy of the nuclei 5626Fe and 20983 Bi in units of MeV from the following data: m ( 5626Fe ) = 55.934939 u m ( 20983 Bi ) = 208.980388 u
📋 Question Details
- Chapter
- Binomial Theorem
- Topic
- Term independent of x in binomial expansion
- Year
- 2021
- Shift
- 18 Mar Shift 2
- Q Number
- Q83
- Type
- Numerical
- NCERT Ref
- Class 11 Mathematics Ch 8: Binomial Theorem
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