Q16.In a photoelectric experiment, ultraviolet light of wavelength 280 nm is used with lithium cathode having work function ϕ = 2. 5 eV. If the wavelength of incident light is switched to 400 nm, find out the change in the stopping potential. (h = 6. 63 × 10−34 J s, c = 3 × 108 m s−1) JEE Main 2021 (26 Aug Shift 1) JEE Main Previous Year Paper (1) 1. 1 V (2) 0. 6 V (3) 1. 3 V (4) 1. 9 V
What This Question Tests
This question requires applying Einstein's photoelectric equation to calculate the stopping potential for two different wavelengths and then finding the change, involving unit conversions.
Concepts Tested
Formulas Used
hν = Φ + eV_s
ν = c/λ
📚 NCERT Sections This Tests
11.5 — In An Experiment On Photoelectric Effect, The Slope Of The Cut-Off Voltage
Physics Class 12 · Chapter 11
11.5 In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10–15 V s. Calculate the value of Planck’s constant.
11.9 — Light Of Wavelength 488 Nm Is Produced By An Argon Laser Which Is
Physics Class 12 · Chapter 11
11.9 Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.
11.3 — The Photoelectric Cut-Off Voltage In A Certain Experiment Is 1.5 V.
Physics Class 12 · Chapter 11
11.3 The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?
📋 Question Details
- Chapter
- Dual Nature of Matter
- Topic
- Photoelectric Effect
- Year
- 2021
- Shift
- 26 Aug Shift 1
- Q Number
- Q16
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 11: Dual Nature of Radiation and Matter
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