Q23.A string is stretched between fixed points separated by 75 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string is (1) 10.5 Hz (2) 105 Hz (3) 1.05 Hz (4) 1050 Hz
What This Question Tests
The question utilizes the concept of harmonics in a stretched string fixed at both ends to determine the fundamental (lowest) resonant frequency from two consecutive resonant frequencies.
Concepts Tested
Formulas Used
f_n = n * f₁
f_n = (n/2L)√(T/μ)
📚 NCERT Sections This Tests
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
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12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
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10.4 In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment.
📋 Question Details
- Chapter
- Waves & Sound
- Topic
- Standing Waves on a String
- Year
- 2006
- Shift
- Unknown
- Q Number
- Q23
- Type
- MCQ
- NCERT Ref
- Class 11 Physics Ch 15: Waves
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