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MathsMediumMCQ2020 · 05 Sep Shift 1

Q53.If 210 + 29 ⋅31 + 28 ⋅32 + … … + 2 ⋅39 + 310 = S −211 , then S is equal to (1) 311 −212 (2) 311 (3) 3112 + 210 (4) 2. 311

What This Question Tests

This problem involves recognizing the given series as a geometric progression and then applying the formula for the sum of 'n' terms of a GP to find the value of S.

Concepts Tested

Identification of Geometric Progression (GP)Formula for sum of GP

Formulas Used

S_n = a(r^n - 1)/(r - 1)

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