Q53.If 210 + 29 ⋅31 + 28 ⋅32 + … … + 2 ⋅39 + 310 = S −211 , then S is equal to (1) 311 −212 (2) 311 (3) 3112 + 210 (4) 2. 311
What This Question Tests
This problem involves recognizing the given series as a geometric progression and then applying the formula for the sum of 'n' terms of a GP to find the value of S.
Concepts Tested
Formulas Used
S_n = a(r^n - 1)/(r - 1)
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📋 Question Details
- Chapter
- Sequences & Series
- Topic
- Sum of a Geometric Progression
- Year
- 2020
- Shift
- 05 Sep Shift 1
- Q Number
- Q53
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 9: Sequences and Series
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