Q74.If the extremities of the base of an isosceles triangle are the points (2a, 0) and (0, a) and the equation of one of the sides is x = 2a, then the area of the triangle, in square units, is : (1) 5 a2 (2) 5 a2 4 2 (3) 25a2 (4) 5a2 4
What This Question Tests
This question combines multiple geometric concepts: finding the third vertex of an isosceles triangle given its base and one side equation, which involves using properties of isosceles triangles, distance formula, and solving linear equations, and then calculating the area.
Concepts Tested
Formulas Used
Distance formula
Slope of a line
Area of triangle = 1/2 * |x1(y2-y3) + x2(y3-y1) + x3(y1-y2)|
Midpoint formula
📚 NCERT Sections This Tests
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📋 Question Details
- Chapter
- Straight Lines
- Topic
- Area of a triangle
- Year
- 2013
- Shift
- 23 Apr Online
- Q Number
- Q74
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 10: Straight Lines
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