Q72.Let y = loge( 1−x21+x2 ), (1) 732 (2) 746 (3) 742 (4) 736
What This Question Tests
This question tests the ability to compute first and second derivatives of a logarithmic function involving a rational expression using the chain rule and quotient rule, followed by substitution.
Concepts Tested
Formulas Used
d/dx (log f(x)) = f'(x)/f(x)
d/dx (u/v) = (vu' - uv')/v^2
📚 NCERT Sections This Tests
8.2 — Name The Following Compounds According To Iupac System Of Nomenclature:
Chemistry Class 12 · Chapter 8
8.2 Name the following compounds according to IUPAC system of nomenclature: (i) CH3CH(CH3)CH2CH2CHO (ii) CH3CH2COCH(C2H5)CH2CH2Cl (iii) CH3CH=CHCHO (iv) CH3COCH2COCH3 (v) CH3CH(CH3)CH2C(CH3)2COCH3 (vi) (CH3)3CCH2COOH (vii) OHCC6H4CHO-p
14.2 — Which Of The Statements Given In Exercise 14.1 Is True For P-Type
Physics Class 12 · Chapter 14
14.2 Which of the statements given in Exercise 14.1 is true for p-type semiconductos.
7.7 — Predict The Major Product Of Acid Catalysed Dehydration Of
Chemistry Class 12 · Chapter 7
7.7 Predict the major product of acid catalysed dehydration of (i) 1-methylcyclohexanol and (ii) butan-1-ol
📋 Question Details
- Chapter
- Differentiation
- Topic
- Higher Order Derivatives
- Year
- 2024
- Shift
- 29 Jan Shift 2
- Q Number
- Q72
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 5: Continuity and Differentiability
More from this Chapter
Q79.Let f(x) = x|x| and g(x) = sin x. Statement-1 : gof is differentiable at x = 0 and its derivative is continuous at that point. Statement-2 : gof is twice differentiable at x = 0 . (1) Statement-1 is true, Statement-2 is true; (2) Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-2 is not a correct explanation for Statement-1 Statement-1 (3) Statement-1 is true, Statement-2 is false (4) Statement-1 is false, Statement-2 is true
Q80.Let y be an implicit function of x defined by x2x −2xx cot y −1 = 0 . Then y′(1) equals (1) −1 (2) 1 (3) log 2 (4) −log 2
Q79.Let f : (−1, 1) →R be a differentiable function with f(0) = −1 and f ′(0) = 1 . Let g(x) = [f(2f(x) + 2)]2 . Then g′(0) = (1) −4 (2) 0 (3) −2 (4) 4
Q78. d2x equals dy2 (1) d2y −1 dy −3 (2) d2y dy −2 −( dx2 ) ( dx ) ( dx2 )( dx ) (3) −( dx2d2y )( dxdy ) −3 (4) ( dx2d2y ) −1