Q14.A charged particle (mass m and charge q) moves along X axis with velocity V0 . When it passes through the → origin it enters a region having uniform electric field E = −Eˆj which extends upto x = d. Equation of path of electron in the region x > d is: qEd qEd (1) y = (x −d) (2) y = ( d2 −x) mv2 mv2 0 0 qEd (3) y = (4) y = qEd2 x mv2 0 mv20
What This Question Tests
This question tests the ability to determine the trajectory of a charged particle moving through a uniform electric field, requiring the application of kinematics equations with constant acceleration.
Concepts Tested
Formulas Used
F = qE
a = F/m
v = u + at
s = ut + (1/2)at²
📚 NCERT Sections This Tests
1.14 — Consider A Uniform Electric Field E = 3 × 103 Î N/C. (A) What Is The
Physics Class 11 · Chapter 1
1.14 Consider a uniform electric field E = 3 × 103 î N/C. (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane? (b) What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
4.11 — In A Chamber, A Uniform Magnetic Field Of 6.5 G (1 G = 10–4 T) Is
Physics Class 11 · Chapter 4
4.11 In a chamber, a uniform magnetic field of 6.5 G (1 G = 10–4 T) is maintained. An electron is shot into the field with a speed of 4.8 × 106 m s–1 normal to the field. Explain why the path of the electron is a circle. Determine the radius of the circular orbit. (e = 1.5 × 10–19 C, me = 9.1×10–31 kg)
📋 Question Details
- Chapter
- Electrostatics
- Topic
- Motion of Charged Particle in Electric Field
- Year
- 2020
- Shift
- 02 Sep Shift 1
- Q Number
- Q14
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 1: Electric Charges and Fields
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