Q89.The distance of the point (1, −2, 4) from the plane passing through the point (1, 2, 2) and perpendicular to the planes x −y + 2z = 3 and 2x −2y + z + 12 = 0, is : (1) 2 (2) √2 (3) 2√2 (4) 1 √2
What This Question Tests
This question involves finding the equation of a plane that passes through a given point and is perpendicular to two other planes. It then requires calculating the perpendicular distance from another point to this newly found plane.
Concepts Tested
Formulas Used
Normal vector of plane n = n₁ x n₂
Equation of plane: A(x-x₀) + B(y-y₀) + C(z-z₀) = 0
Distance of point from plane
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📋 Question Details
- Chapter
- 3D Geometry
- Topic
- Equation of plane
- Year
- 2016
- Shift
- 09 Apr Online
- Q Number
- Q89
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 11: Three Dimensional Geometry
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