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PhysicsMediumNumerical2025 · 24 Jan Shift 1

Q46.A current of 5A exists in a square loop of side 1 m . Then the magnitude of the magnetic field B at the centre √2 of the square loop will be p × 10−6 T. where, value of p is _____ . [ Take μ0 = 4π × 10−7TmA−1].

What This Question Tests

This question requires calculating the magnetic field at the center of a square loop by summing the contributions from its four sides using the formula for a finite straight wire.

Concepts Tested

Magnetic field due to a finite straight current-carrying wireSuperposition principle

Formulas Used

B = (μ₀I / 4πd) (sinθ₁ + sinθ₂)

B_square = 4 * B_side

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