Q55.The number of sp3 hybridised carbons in an acyclic neutral compound with molecular formula C4H5N is
What This Question Tests
This question tests the ability to determine the number of sp3 hybridized carbons in a given acyclic molecular formula (C4H5N) by drawing possible stable structures and applying hybridization rules.
Concepts Tested
📚 NCERT Sections This Tests
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
5.12 — Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of
Chemistry Class 11 · Chapter 5
5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
📋 Question Details
- Chapter
- GOC
- Topic
- Hybridization
- Year
- 2022
- Shift
- 25 Jul Shift 1
- Q Number
- Q55
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 12: Organic Chemistry - Some Basic Principles and Techniques
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