Q28.The current of 5 A flows in a square loop of sides 1 m is placed in air. The magnetic field at the centre of the loop is X√2 × 10-7 T. The value of X is _________.
What This Question Tests
This problem requires calculating the magnetic field produced by each segment of a square loop at its center and then using vector addition (superposition) to find the total field.
Concepts Tested
Formulas Used
B = (μ₀I / 4πd) * (sinθ1 + sinθ2)
📚 NCERT Sections This Tests
4.4 — A Horizontal Overhead Power Line Carries A Current Of 90 A In East To
Physics Class 11 · Chapter 4
4.4 A horizontal overhead power line carries a current of 90 A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5 m below the line?
4.6 — A 3.0 Cm Wire Carrying A Current Of 10 A Is Placed Inside A Solenoid
Physics Class 11 · Chapter 4
4.6 A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
4.9 — A Square Coil Of Side 10 Cm Consists Of 20 Turns And Carries A Current
Physics Class 11 · Chapter 4
4.9 A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30º with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque experienced by the coil?
📋 Question Details
- Chapter
- Magnetic Effects of Current
- Topic
- Magnetic field at the center of a square loop
- Year
- 2024
- Shift
- 30 Jan Shift 2
- Q Number
- Q28
- Type
- Numerical
- NCERT Ref
- Class 12 Physics Ch 4: Moving Charges and Magnetism
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