Q52.The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is: (1) Fe2+ (2) Co2+ (3) Ni2+ (4) Mn2+
What This Question Tests
This question tests the application of Crystal Field Theory to determine the d-electron configuration and calculate the number of unpaired electrons in high-spin and low-spin octahedral complexes for different metal ions.
Concepts Tested
📚 NCERT Sections This Tests
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
5.23 — Give The Oxidation State, D Orbital Occupation And Coordination Number Of
Chemistry Class 11 · Chapter 5
5.23 Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes: (i) K3[Co(C2O4)3] (iii) (NH4)2[CoF4] (ii) cis-[CrCl2(en)2]Cl (iv) [Mn(H2O)6]SO4
5.18 — What Is Crystal Field Splitting Energy? How Does The Magnitude Of Do Decide
Chemistry Class 11 · Chapter 5
5.18 What is crystal field splitting energy? How does the magnitude of Do decide the actual configuration of d orbitals in a coordination entity?
📋 Question Details
- Chapter
- d-block & f-block Elements
- Topic
- Crystal Field Theory
- Year
- 2019
- Shift
- 10 Jan Shift 2
- Q Number
- Q52
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 9: Coordination Compounds
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