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PhysicsMediumNumerical2024 · 04 Apr Shift 2

Q29.A light ray is incident on a glass slab of thickness 4√3 cm and refractive index √2 . The angle of incidence is equal to the critical angle for the glass slab with air. The lateral displacement of ray after passing through glass slab is _____ cm . ( Given sin 15∘= 0.25)

What This Question Tests

This question combines the concepts of critical angle, Snell's law, and the calculation of lateral displacement when light passes through a glass slab.

Concepts Tested

Snell's LawCritical angleLateral shift due to a glass slab

Formulas Used

sin(ic) = 1/n

n1 sin(i) = n2 sin(r)

Lateral Shift = t sin(i-r) / cos(r)

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