Q80.The equation of a normal to the curve, sin y = x sin( π3 + y) at x = 0, is: (1) 2x −√3 y = 0 (2) 2y −√3 x = 0 (3) 2y + √3 x = 0 (4) 2x + √3 y = 0
What This Question Tests
The problem asks for the equation of the normal to an implicitly defined curve at a specific point. It requires finding the derivative using implicit differentiation and then calculating the slope of the normal.
Concepts Tested
Formulas Used
dy/dx for implicit functions
Slope of normal = -1 / (slope of tangent)
y - y1 = m(x - x1)
📚 NCERT Sections This Tests
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
9.15 — Apply Mirror Equation And The Condition:
Physics Class 12 · Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
📋 Question Details
- Chapter
- Applications of Derivatives
- Topic
- Equation of normal to a curve
- Year
- 2015
- Shift
- 11 Apr Online
- Q Number
- Q80
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 6: Applications of Derivatives
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