Q61.Let α, β be the roots of the quadratic equation x2 + √6x + 3 = 0. Then α15+β15+α10+β10α23+β23+α14+β14 (1) 81 (2) 9 (3) 72 (4) 729
What This Question Tests
This question involves finding the roots of a quadratic equation that are complex numbers, expressing them in polar form, and then using De Moivre's theorem to calculate higher powers before substituting into a given expression.
Concepts Tested
Formulas Used
x = (-b ± sqrt(b^2 - 4ac))/(2a)
z^n = r^n(cos(nθ) + i sin(nθ))
📚 NCERT Sections This Tests
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
9.15 — Apply Mirror Equation And The Condition:
Physics Class 12 · Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
2.2 — A Regular Hexagon Of Side 10 Cm Has A Charge 5 Mc At Each Of Its
Physics Class 11 · Chapter 2
2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.
📋 Question Details
- Chapter
- Complex Numbers
- Topic
- Roots of Unity
- Year
- 2023
- Shift
- 12 Apr Shift 1
- Q Number
- Q61
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 5: Complex Numbers and Quadratic Equations
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