RankLab
Back to Questions
MathsMediumMCQ2021 · 25 Jul Shift 2

Q68.Let the equation of the pair of lines, y = px and y = qx, can be written as (y −px)(y −qx) = 0. Then the equation of the pair of the angle bisectors of the lines x2 −4xy −5y2 = 0 is: (1) x2 −3xy + y2 = 0 (2) x2 + 4xy −y2 = 0 (3) x2 + 3xy −y2 = 0 (4) x2 −3xy −y2 = 0

What This Question Tests

This question tests the knowledge of finding the equation of the pair of angle bisectors for a given pair of lines represented by a second-degree equation.

Concepts Tested

Equation of pair of linesEquation of angle bisectors

Formulas Used

Equation of pair of angle bisectors: (x^2 - y^2)/(a-b) = xy/h for ax^2 + 2hxy + by^2 = 0

📚 NCERT Sections This Tests

2.1Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At

Physics Class 11 · Chapter 2

72% match

2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

5.12Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of

Chemistry Class 11 · Chapter 5

71% match

5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?

9.15Apply Mirror Equation And The Condition:

Physics Class 12 · Chapter 9

70% match

9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.