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PhysicsMediumMCQ2013 · 23 Apr Online

Q26.Electrons are accelerated through a potential difference V and protons are accelerated through a potential difference 4 V. The de-Broglie wavelengths are λe and λp for electrons and protons respectively. The ratio of λe is given by: (given me is mass of electron and mp is mass of proton). λp (1) = λp λe = √mpme (2) λpλe √memp (3) = λp λe = 12 √memp (4) λpλe 2√mpme

What This Question Tests

This question requires combining the de-Broglie wavelength formula with the kinetic energy gained by a charged particle accelerated through a potential difference to find the ratio of wavelengths for an electron and a proton.

Concepts Tested

de-Broglie wavelengthKinetic energy of charged particles in potential difference

Formulas Used

λ = h / p

p = √(2mK)

K = qV

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