RankLab
Back to Questions
MathsMediumNumerical2020 · 05 Sep Shift 1

Q75.Four fair dice are thrown independently 27 times. Then the expected number of times, at least two dice show up a three or a five, is JEE Main 2020 (05 Sep Shift 1) JEE Main Previous Year Paper

What This Question Tests

The question combines probability calculations for a single trial with the concept of binomial distribution and its expected value, requiring calculation of probability for 'at least two successes'.

Concepts Tested

Probability of an eventBinomial distributionExpected value of binomial distribution

Formulas Used

P(E) = n(E)/n(S)

P(X ≥ k) = 1 - P(X < k)

Expected value E(X) = n*p

📚 NCERT Sections This Tests

13.2Obtain The Binding Energy Of The Nuclei 5626Fe And 20983 Bi In Units Of

Physics Class 12 · Chapter 13

68% match

13.2 Obtain the binding energy of the nuclei 5626Fe and 20983 Bi in units of MeV from the following data: m ( 5626Fe ) = 55.934939 u m ( 20983 Bi ) = 208.980388 u

2.2A Regular Hexagon Of Side 10 Cm Has A Charge 5 Mc At Each Of Its

Physics Class 11 · Chapter 2

67% match

2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.

11.6The Threshold Frequency For A Certain Metal Is 3.3 × 1014 Hz. If Light

Physics Class 12 · Chapter 11

67% match

11.6 The threshold frequency for a certain metal is 3.3 × 1014 Hz. If light of frequency 8.2 × 1014 Hz is incident on the metal, predict the cut- off voltage for the photoelectric emission.

📋 Question Details

Chapter
Probability
Topic
Expected value and binomial distribution
Year
2020
Shift
05 Sep Shift 1
Q Number
Q75
Type
Numerical
NCERT Ref
Class 12 Mathematics Ch 13: Probability

More from this Chapter

Q90.One ticket is selected at random from 50 tickets numbered 00, 01, 02, … , 49. Then the probability that the sum of the digits on the selected ticket is 8 , given that the product of these digits is zero, equals (1) 1 (2) 1 14 7 (3) 5 (4) 1 14 50 JEE Main 2009 JEE Main Previous Year Paper

2009
Medium

Q89.Four numbers are chosen at random (without replacement) from the set {1, 2, 3, … . , 20} . Statement-1: The probability that the chosen numbers when arranged in some order will form an AP is 1 . Statement-2: If the 85 four chosen numbers from an AP, then the set of all possible values of common difference is {±1, ±2, ±3, ±4, ±5}. (1) Statement-1 is true, Statement-2 is true; (2) Statement-1 is true, Statement-2 is false Statement-2 is not the correct explanation for Statement-1 (3) Statement-1 is false, Statement-2 is true (4) Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation for Statement-1

2010
Hard

Q90.An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colour is (1) 2 (2) 1 7 21 (3) 2 (4) 1 23 3 JEE Main 2010 JEE Main Previous Year Paper

2010
Medium

Q89.Consider 5 independent Bernoulli's trials each with probability of success p . If the probability of at least one failure is greater than or equal to 31 , then p lies in the interval 32 (1) ( 34 , 1112 ] (2) [0, 12 ] (3) ( 1112 , 1] (4) ( 12 , 34 ]

2011
Medium
More Mathematics questions