Q42.Molar mass of the hydrocarbon (X) which on ozonolysis consumes one mole of O3 per mole of (X) and gives one mole each of ethanal and propanone is ______ g mol–1 (Molar mass of C : 12 g mol–1 , H : 1 g mol–1 )
What This Question Tests
This question tests the ability to deduce the structure of an alkene from its ozonolysis products and then calculate its molar mass, which is a common application in organic chemistry.
Concepts Tested
Formulas Used
Molar mass calculation
📚 NCERT Sections This Tests
8.19 — An Organic Compound Contains 69.77% Carbon, 11.63% Hydrogen And Rest Oxygen.
Chemistry Class 12 · Chapter 8
8.19 An organic compound contains 69.77% carbon, 11.63% hydrogen and rest oxygen. The molecular mass of the compound is 86. It does not reduce Tollens’ reagent but forms an addition compound with sodium hydrogensulphite and give positive iodoform test. On vigorous oxidation it gives ethanoic and propanoic acid. Write the possible structure of the compound.
8.3 — Draw The Structures Of The Following Compounds.
Chemistry Class 12 · Chapter 8
8.3 Draw the structures of the following compounds. (i) 3-Methylbutanal (ii) p-Nitropropiophenone (iii) p-Methylbenzaldehyde (iv) 4-Methylpent-3-en-2-one (v) 4-Chloropentan-2-one (vi) 3-Bromo-4-phenylpentanoic acid (vii) p,p’-Dihydroxybenzophenone (viii) Hex-2-en-4-ynoic acid
8.17 — Complete Each Synthesis By Giving Missing Starting Material, Reagent Or Products
Chemistry Class 12 · Chapter 8
8.17 Complete each synthesis by giving missing starting material, reagent or products
📋 Question Details
- Chapter
- Aldehydes Ketones Carboxylic Acids
- Topic
- Ozonolysis of alkenes
- Year
- 2023
- Shift
- 08 Apr Shift 1
- Q Number
- Q42
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 13: Hydrocarbons
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