Q68.The equations of the sides AB, BC & CA of a triangle ABC are 2x + y = 0 , x + py = 21a (a ≠0) and x −y = 3 respectively. Let P(2, a) be the centroid of the triangle ABC , then (BC)2 is equal to
What This Question Tests
This question tests the ability to find the vertices of a triangle by solving simultaneous linear equations and then using the centroid formula to find unknown parameters and the length of a side.
Concepts Tested
Formulas Used
Intersection of lines: solve system of equations
Centroid G = ((x1+x2+x3)/3, (y1+y2+y3)/3)
Distance formula: d = √((x2-x1)² + (y2-y1)²)
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📋 Question Details
- Chapter
- Straight Lines
- Topic
- Centroid of a triangle
- Year
- 2023
- Shift
- 24 Jan Shift 2
- Q Number
- Q68
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 10: Straight Lines
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