Q26.In 5 minutes , a body cools from 75 °C to 65 °C at room temperature of 25 °C. The temperature of body at the end of next 5 minutes is ∘C.
What This Question Tests
This question tests the application of Newton's Law of Cooling in two stages to determine the final temperature of a body after successive time intervals.
Concepts Tested
Formulas Used
(T1 - T2)/t = K * ((T1 + T2)/2 - T_room)
📚 NCERT Sections This Tests
3.26 — The Decomposition Of Hydrocarbon Follows The Equation
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3.26 The decomposition of hydrocarbon follows the equation k = (4.5 × 1011s–1) e-28000K/T Calculate Ea. 87 Chemical Kinetics Reprint 2025-26
6.11 — Dynamics Of Rotational
Physics Class 11 · Chapter 6
6.11 Dynamics of rotational the motion of extended bodies. motion about a fixed axis A large class of problems with extended bodies can be
3.22 — The Rate Constant For The Decomposition Of N2O5 At Various Temperatures
Chemistry Class 11 · Chapter 3
3.22 The rate constant for the decomposition of N2O5 at various temperatures is given below: T/°C 0 20 40 60 80 105 × k/s-1 0.0787 1.70 25.7 178 2140 Draw a graph between ln k and 1/T and calculate the values of A and Ea. Predict the rate constant at 30° and 50°C.
📋 Question Details
- Chapter
- Thermodynamics & KTG
- Topic
- Newton's Law of Cooling
- Year
- 2021
- Shift
- 22 Jul Shift 1
- Q Number
- Q26
- Type
- Numerical
- NCERT Ref
- Class 11 Physics Ch 11: Thermal Properties of Matter
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