Q79.Let X have a binomial distribution B(n, p) such that the sum and the product of the mean and variance of X are 24 and 128 respectively. If P(X > n −3) = 2nk , then k is equal to (1) 528 (2) 529 (3) 629 (4) 630
What This Question Tests
This question uses the properties of mean and variance of a binomial distribution to find 'n' and 'p', and then applies the binomial probability formula for P(X > n-3).
Concepts Tested
Formulas Used
Mean = np
Variance = npq
P(X=k) = nCk p^k q^(n-k)
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📋 Question Details
- Chapter
- Probability
- Topic
- Binomial distribution
- Year
- 2022
- Shift
- 27 Jul Shift 2
- Q Number
- Q79
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 13: Probability
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