Q14.A charge Q is placed at a distance a/2 above the centre of the square surface of edge a as shown in the figure. The electric flux through the square surface is: (1) Q (2) Q 3ε0 6ε0 (3) Q (4) Q 2ε0 ε0
What This Question Tests
This question applies Gauss's Law to calculate the electric flux through a square surface due to a charge placed symmetrically above its center, demonstrating the use of symmetry to simplify flux calculations.
Concepts Tested
Formulas Used
Φ = Q_enclosed / ε₀
📚 NCERT Sections This Tests
1.17 — A Point Charge +10 Mc Is A Distance 5 Cm Directly Above The Centre
Physics Class 11 · Chapter 1
1.17 A point charge +10 mC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown in Fig. 1.31. What is the magnitude of the electric flux through the square? (Hint: Think of the square as one face of a cube with edge 10 cm.) FIGURE 1.31
1.18 — A Point Charge Of 2.0 Mc Is At The Centre Of A Cubic Gaussian
Physics Class 11 · Chapter 1
1.18 A point charge of 2.0 mC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?
1.14 — Consider A Uniform Electric Field E = 3 × 103 Î N/C. (A) What Is The
Physics Class 11 · Chapter 1
1.14 Consider a uniform electric field E = 3 × 103 î N/C. (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane? (b) What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?
📋 Question Details
- Chapter
- Electrostatics
- Topic
- Electric flux, Gauss's Law
- Year
- 2018
- Shift
- 15 Apr Shift 1 Online
- Q Number
- Q14
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 1: Electric Charges and Fields
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