Q37.The ionization enthalpy of hydrogen atom is 1.312 × 106Jmol−1 . The energy required to excite the electron in the atom from n = 1 to n = 2 is (1) 8.51 × 105Jmol−1 (2) 6.56 × 105Jmol−1 (3) 7.56 × 105Jmol−1 (4) 9.84 × 105Jmol−1
What This Question Tests
The ionization enthalpy of hydrogen is the energy to excite an electron from n=1 to n=∞ (E₁ = -1.312 × 10⁶ Jmol⁻¹). The energy of the n=2 state is E₂ = E₁/2². The energy required to excite from n=1 to n=2 is ΔE = E₂ - E₁ = (E₁/4) - E₁ = -3E₁/4. So, ΔE = -3/4 * (-1.312 × 10⁶ Jmol⁻¹) = 9.84 × 10⁵ Jmol⁻¹.
Concepts Tested
Formulas Used
E_n = E₁/n²
ΔE = E₂ - E₁
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
📋 Question Details
- Chapter
- Atomic Structure
- Topic
- Bohr's Model, Ionization energy, Excitation energy
- Year
- 2008
- Shift
- Unknown
- Q Number
- Q37
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 2: Structure of Atom
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