Q12.A force of 10 N acts on a charged particle placed between two plates of a charged capacitor. If one plate of capacitor is removed, then the force acting on that particle will be. (1) 5 N (2) 10 N (3) 20 N (4) Zero
What This Question Tests
This question assesses the understanding of the electric field produced by charged plates and how it changes when one plate is removed, affecting the force on a charge.
Concepts Tested
Formulas Used
F = qE
E_total = E_plate1 + E_plate2
E_single_plate = σ / (2ε₀)
📚 NCERT Sections This Tests
2.5 — A Parallel Plate Capacitor With Air Between The Plates Has A
Physics Class 11 · Chapter 2
2.5 A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10–12 F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
2.4 — A Spherical Conductor Of Radius 12 Cm Has A Charge Of 1.6 × 10–7C
Physics Class 11 · Chapter 2
2.4 A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field (a) inside the sphere (b) just outside the sphere (c) at a point 18 cm from the centre of the sphere?
📋 Question Details
- Chapter
- Electrostatics
- Topic
- Electric field
- Year
- 2022
- Shift
- 27 Jun Shift 1
- Q Number
- Q12
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 2: Electrostatic Potential and Capacitance
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