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MathsMediumMCQ2015 · 04 Apr

Q88.The distance of the point (1, 0, 2) from the point of intersection of the line x−23 = y+14 = z−212 and the plane x −y + z =16, is (1) 13 (2) 2√14 (3) 8 (4) 3√21

What This Question Tests

The question tests the ability to find the point of intersection of a given line and a plane by substituting the parametric form of the line into the plane's equation, and then calculating the distance between two points in 3D space.

Concepts Tested

Equation of a line in symmetric formEquation of a planePoint of intersection of line and planeDistance formula in 3D

Formulas Used

Line: (x-x₀)/a = (y-y₀)/b = (z-z₀)/c = λ

Plane: Ax+By+Cz=D

Distance between two points: √((x₂-x₁)²+(y₂-y₁)²+(z₂-z₁)² )

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