Q55.A solution containing 10 g of an electrolyte AB2 in 100 g of water boils at 100.52∘C . The degree of ionization of the electrolyte (α) is _______ ×10−1 . (nearest integer) [Given : Molar mass of AB2 = 200 g mol−1, Kb (molal boiling point elevation const. of water) = 0.52 K kg mol−1 , boiling point of water = 100∘C; AB2 ionises as AB2 →A2+ + 2 B−]
What This Question Tests
This question combines the elevation in boiling point formula with the van't Hoff factor to calculate the degree of ionization for a given electrolyte.
Concepts Tested
Formulas Used
ΔT_b = i * K_b * m
i = 1 + α(n-1)
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📋 Question Details
- Chapter
- Solutions
- Topic
- Colligative Properties (Elevation in Boiling Point)
- Year
- 2024
- Shift
- 08 Apr Shift 1
- Q Number
- Q55
- Type
- Numerical
- NCERT Ref
- Class 12 Chemistry Ch 2: Solutions
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