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PhysicsMediumNumerical2021 · 31 Aug Shift 1

Q25.A wire having a linear mass density 9. 0 × 10−4 kg m−1 is stretched between two rigid supports with a tension of 900 N. The wire resonates at a frequency of 500 Hz. The next higher frequency at which the same wire resonates is 550 Hz. The length of the wire is ___________ m.

What This Question Tests

This question involves determining the length of a string by using the relationship between consecutive resonant frequencies and the wave speed, which depends on tension and linear mass density.

Concepts Tested

Standing wavesResonance frequenciesLinear mass densityWave speed in string

Formulas Used

v = √(T/μ)

f_n = (nv) / (2L)

f_n+1 - f_n = v / (2L)

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