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MathsMediumAssertion Reasoning2009 · Unknown

Q70.Statement-1: ∼(p ↔∼q) is equivalent to p ↔q . Statement-2 : ∼(p ↔∼q) is a tautology. (1) Statement-1 is true, Statement-2 is true; (2) Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-2 is not a correct explanation for Statement-1 Statement-1 (3) Statement-1 is true, Statement-2 is false (4) Statement-1 is false, Statement-2 is true

What This Question Tests

This question assesses the ability to determine logical equivalence between compound statements involving biconditional and negation, and to identify if a statement is a tautology, typically by using truth tables or known logical equivalences.

Concepts Tested

Logical connectives (biconditional, negation)Truth tablesLogical equivalenceTautology

Formulas Used

p ↔ q ≡ (p → q) ∧ (q → p)

p ↔ q ≡ (p ∧ q) ∨ (~p ∧ ~q)

~(~p) ≡ p

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📋 Question Details

Chapter
Mathematical Reasoning
Topic
Logical equivalence and tautology
Year
2009
Shift
Unknown
Q Number
Q70
Type
Assertion Reasoning
NCERT Ref
Class 11 Mathematics Ch 14: Mathematical Reasoning
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