Q24.In a closed organ pipe, the frequency of fundamental note is 30 Hz. A certain amount of water is now poured in the organ pipe so that the fundamental frequency is increased to 110 Hz. If the organ pipe has a cross- sectional area of 2 cm2 , the amount of water poured in the organ tube is ________ g. (Take speed of sound in air is 330 m s−1 )
What This Question Tests
This question requires applying the formula for the fundamental frequency of a closed organ pipe to determine its initial and final lengths, and then calculating the mass of water added based on the change in length.
Concepts Tested
Formulas Used
f_n = (2n-1)v / 4L
f_fundamental = v / 4L
Mass = Density × Volume
Volume = Area × Height
📚 NCERT Sections This Tests
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2.5 A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10–12 F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
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9.3 A tank is filled with water to a height of 12.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 9.4 cm. What is the refractive index of water? If water is replaced by a liquid of refractive index 1.63 up to the same height, by what distance would the microscope have to be moved to focus on the needle again?
📋 Question Details
- Chapter
- Waves & Sound
- Topic
- Organ pipes
- Year
- 2024
- Shift
- 30 Jan Shift 1
- Q Number
- Q24
- Type
- Numerical
- NCERT Ref
- Class 11 Physics Ch 15: Waves
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