Q72. (27+x) 31 −3 lim 2 equals x→0 9−(27+x) 3 (1) −16 (2) 61 (3) 3 1 (4) −13
What This Question Tests
This question requires evaluating a limit of an indeterminate form (0/0) by applying L'Hôpital's Rule or by algebraic manipulation/substitution, testing derivative skills for fractional powers.
Concepts Tested
Formulas Used
L'Hôpital's Rule: lim(f(x)/g(x)) = lim(f'(x)/g'(x)) when it's 0/0 or ∞/∞ form
📚 NCERT Sections This Tests
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
📋 Question Details
- Chapter
- Limits & Continuity
- Topic
- Evaluation of limits
- Year
- 2018
- Shift
- 16 Apr Online
- Q Number
- Q72
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 13: Limits and Derivatives
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