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PhysicsMediumMulti concept2015 · 04 Apr

Q14. Two long currents carrying thin wires, both with current I , are held by insulating threads of length L and are in equilibrium as shown in the figure, with threads making an angle ' θ ' with the vertical. If wires have a mass λ per unit length then the value of I is: ( g = gravitational acceleration) (1) (2) tanθ √πλgLμ0 sinθ√πλgLμ0 cosθ (3) (4) tanθ 2sinθ√πλgLμ0cosθ 2√πgLμ0

What This Question Tests

This question combines magnetic force between current-carrying wires with equilibrium under gravity and tension. It requires drawing a free-body diagram for one wire and resolving forces to find the current 'I'.

Concepts Tested

Magnetic force between parallel wiresNewton's laws of motionEquilibrium of forcesTension in string

Formulas Used

F_magnetic = (μ₀ I₁ I₂ L) / (2πd)

mg = λLg

ΣF_x = 0

ΣF_y = 0

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