Q67.The smallest natural number ๐ , such that the coefficient of ๐ฅ in the expansion of ๐ฅ2 + is ๐๐ถ23 , is ๐ฅ3 (1) 58 (2) 38 (3) 35 (4) 23 3
What This Question Tests
The problem requires finding the general term in a binomial expansion, determining the value of 'r' for a specific power of x, and then solving for 'n' given the coefficient.
Concepts Tested
Formulas Used
Tr+1 = nCr * x^(n-r) * y^r
๐ NCERT Sections This Tests
12.7 โ The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 ยท Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3ร10โ11 m. What are the radii of the n = 2 and n =3 orbits?
5.23 โ Give The Oxidation State, D Orbital Occupation And Coordination Number Of
Chemistry Class 11 ยท Chapter 5
5.23 Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes: (i) K3[Co(C2O4)3] (iii) (NH4)2[CoF4] (ii) cis-[CrCl2(en)2]Cl (iv) [Mn(H2O)6]SO4
1.3 โ Define The Following Terms:
Chemistry Class 11 ยท Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
๐ Question Details
- Chapter
- Binomial Theorem
- Topic
- General term in binomial expansion
- Year
- 2019
- Shift
- 10 Apr Shift 2
- Q Number
- Q67
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 8: Binomial Theorem
More from this Chapter
Q89.In the binomial expansion of (a โb)n, n โฅ5 , the sum of 5th and 6th terms is zero, then ab equals (1) 5 (2) 6 nโ4 nโ5 (3) nโ5 (4) nโ4 6 5
Q90.The sum of the series 20C0 โ20C1 + 20C2 โ20C3 + โฆ โโฆ + 20C10 is (1) โ20C10 (2) 12 20C10 (3) 0 (4) 20C10
Q77.Statement-1: โnr=0(r + 1)nCr = (n + 2)2nโ1 Statement -2: โnr=0(r + 1)nCrxr = (1 + x)n + nx(1 + x)nโ1 . JEE Main 2008 JEE Main Previous Year Paper (1) Statement โ1 is false, Statement โ2 is true (2) Statement โ1 is true, Statement โ2 is true, Statement โ2 is a correct explanation for Statement โ1 (3) Statement โ1 is true, Statement โ2 is true; (4) Statement โ1 is true, Statement โ2 is false. Statement โ2 is not a correct explanation for Statement โ1.
Q65.The remainder left out when 82n โ(62)2n+1 is divided by 9 is (1) 0 (2) 2 (3) 7 (4) 8