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PhysicsMediumMCQ2023 · 13 Apr Shift 1

Q11. The figure shows a liquid of given density flowing steadily in horizontal tube of varying cross-section. Cross- sectional areas at A is 1. 5 cm2, and B is 25 mm2, if the speed of liquid at B is 60 cm s−1 then (PA–PB) is (Given PA and PB are liquid pressures at A and B points. Density ρ = 1000 kg m−3 A and B are on the axis of tube) (1) 135 Pa (2) 27 Pa (3) 175 Pa (4) 36 Pa 5 ) 2 v, when v is the average

What This Question Tests

This question applies both the equation of continuity and Bernoulli's principle to calculate the pressure difference in a horizontal tube with varying cross-sections, requiring careful unit conversions.

Concepts Tested

Equation of continuityBernoulli's principleFluid dynamicsUnit conversion

Formulas Used

A₁v₁ = A₂v₂

P + (1/2)ρv² = constant (for horizontal flow)

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