Q89.If the mean and the variance of a binomial variate X are 2 & 1 respectively, then the probability that X takes a value greater than or equal to one is: (1) 1 (2) 9 16 16 (3) 3 (4) 15 4 16
What This Question Tests
This problem involves a binomial distribution. It tests the ability to find the parameters 'n' and 'p' from the given mean and variance, and then calculate the probability of X being greater than or equal to one using the complementary probability method.
Concepts Tested
Formulas Used
Mean (np)
Variance (npq)
P(X=k) = C(n,k) p^k q^(n-k)
P(X>=1) = 1 - P(X=0)
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📋 Question Details
- Chapter
- Probability
- Topic
- Binomial distribution
- Year
- 2015
- Shift
- 11 Apr Online
- Q Number
- Q89
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 13: Probability
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