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MathsMediumMCQ2015 · 11 Apr Online

Q89.If the mean and the variance of a binomial variate X are 2 & 1 respectively, then the probability that X takes a value greater than or equal to one is: (1) 1 (2) 9 16 16 (3) 3 (4) 15 4 16

What This Question Tests

This problem involves a binomial distribution. It tests the ability to find the parameters 'n' and 'p' from the given mean and variance, and then calculate the probability of X being greater than or equal to one using the complementary probability method.

Concepts Tested

Mean and variance of binomial distributionProbability mass function of binomial distributionComplementary probability

Formulas Used

Mean (np)

Variance (npq)

P(X=k) = C(n,k) p^k q^(n-k)

P(X>=1) = 1 - P(X=0)

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📋 Question Details

Chapter
Probability
Topic
Binomial distribution
Year
2015
Shift
11 Apr Online
Q Number
Q89
Type
MCQ
NCERT Ref
Class 12 Mathematics Ch 13: Probability

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