Q48. The reaction of with bromine and KOH gives RNH2 as the end product. Which one of the following is the intermediate product formed in this reaction? (1) (2) R - NH - Br (3) R - N = C = O (4)
What This Question Tests
This question tests the recall of the mechanism of the Hofmann bromamide degradation reaction and the identification of a key intermediate, the isocyanate.
Concepts Tested
📚 NCERT Sections This Tests
9.9 — Give The Structures Of A, B And C In The Following Reactions:
Chemistry Class 12 · Chapter 9
9.9 Give the structures of A, B and C in the following reactions: B NaOH Br 2 C (i) CH 3 CH 2 I NaCN A Partial OHhydrolysis CuCN H 2 O/H NH 3 (ii) C 6 H 5 N 2 Cl A B C 4 B HNO 2 C (iii) CH 3 CH 2 Br KCN A LiAlH 0 C 2 2 O/H HCl B H C (iv) C6 H 5 NO 2 Fe/HCl A NaNO273 K 3 A NaOBr B NaNO 2 /HCl C (v) CH 3 COOH NH 2 B C 6 H 5 OH C (vi) C6 H 5 NO 2 Fe/HCl A HNO273K 279 Amines Reprint 2025-26
9.7 — Write Short Notes On The Following:
Chemistry Class 12 · Chapter 9
9.7 Write short notes on the following: (i) Carbylamine reaction (ii) Diazotisation (iii) Hofmann’s bromamide reaction (iv) Coupling reaction (v) Ammonolysis (vi) Acetylation (vii) Gabriel phthalimide synthesis.
6.21 — Primary Alkyl Halide C4H9Br (A) Reacted With Alcoholic Koh To Give Compound (B).
Chemistry Class 12 · Chapter 6
6.21 Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.
📋 Question Details
- Chapter
- Nitrogen Compounds
- Topic
- Hofmann Bromamide Degradation
- Year
- 2022
- Shift
- 25 Jun Shift 1
- Q Number
- Q48
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 13: Nitrogen Compounds
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