Q80.Let f(1) = −2 and f ′(x) ≥4.2 for 1 ≤x ≤6 . The possible value of f(6) lies in the interval : (1) [15, 19) (2) (−∞, 12) (3) [12, 15) (4) [19, ∞)
What This Question Tests
This question requires applying the Mean Value Theorem to establish an inequality for the function's value at a specific point, given a lower bound for its derivative over an interval.
Concepts Tested
Formulas Used
f'(c) = (f(b) - f(a)) / (b - a)
📚 NCERT Sections This Tests
9.15 — Apply Mirror Equation And The Condition:
Physics Class 12 · Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
📋 Question Details
- Chapter
- Applications of Derivatives
- Topic
- Mean Value Theorem
- Year
- 2013
- Shift
- 25 Apr Online
- Q Number
- Q80
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 5: Continuity and Differentiability
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