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PhysicsHardMCQ2014 · 12 Apr Online

Q27.A beam of light has two wavelengths of 4972Å and 6216Å with a total intensity of 3.6 × 10−3 Wm−2 equally distributed among the two wavelengths. The beam falls normally on an area of 1 cm2 of a clean metallic surface of work function 2.3eV. Assume that there is no loss of light by reflection and that each capable photon ejects one electron. The number of photoelectrons liberated in 2 s is approximately: (1) 6 × 1011 (2) 9 × 1011 (3) 11 × 1011 (4) 15 × 1011

What This Question Tests

This multi-concept question requires calculating the number of photons for two different wavelengths from given total intensity, checking which photons are energetic enough to cause photoemission, and then summing the emitted photoelectrons.

Concepts Tested

Photon energyWork functionIntensity of lightNumber of photons

Formulas Used

E = hc/λ

I = N_p hf / AΔt

N_e = N_p_capable

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