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ChemistryMediumMCQ2025 · 28 Jan Shift 2

Q68.Identify the inorganic sulphides that are yellow in colour : (A) (NH4)2 S (B) Pbs (C) Cus (D) As2 S3 (E) As2 S5 Choose the correct answer from the options given below : (1) (A), (D) and (E) only (2) (D) and (E) only (3) (A) and (B) only (4) (A) and (C) only

What This Question Tests

This question assesses knowledge of the characteristic colors of various inorganic sulphide compounds, particularly those encountered in qualitative analysis schemes.

Concepts Tested

Inorganic compoundsSulphidesQualitative analysisColors of precipitates

📚 NCERT Sections This Tests

5.13Aqueous Copper Sulphate Solution (Blue In Colour) Gives:

Chemistry Class 11 · Chapter 5

74% match

5.13 Aqueous copper sulphate solution (blue in colour) gives: (i) a green precipitate with aqueous potassium fluoride and (ii) a bright green solution with aqueous potassium chloride. Explain these experimental results.

5.14What Is The Coordination Entity Formed When Excess Of Aqueous Kcn Is

Chemistry Class 11 · Chapter 5

74% match

5.14 What is the coordination entity formed when excess of aqueous KCN is added to an aqueous solution of copper sulphate? Why is it that no precipitate of copper sulphide is obtained when H2S(g) is passed through this solution?

5.29Amongst The Following Ions Which One Has The Highest Magnetic Moment Value?

Chemistry Class 11 · Chapter 5

72% match

5.29 Amongst the following ions which one has the highest magnetic moment value? (i) [Cr(H2O)6]3+ (ii) [Fe(H2O)6] 2+ (iii) [Zn(H2O)6]2+ 5.30 Amongst the following, the most stable complex is (i) [Fe(H2O)6]3+ (ii) [Fe(NH3)6] 3+ (iii) [Fe(C2O4)3]3– (iv) [FeCl6] 3– 5.31 What will be the correct order for the wavelengths of absorption in the visible region for the following: [Ni(NO2)6] 4–, [Ni(NH3)6] 2+, [Ni(H2O)6] 2+ ? Answers to Some Intext Questions 5.1 (i) [Co(NH3)4(H2O)2]Cl3 (iv) [Pt(NH3)BrCl(NO2)]– (ii) K2[Ni(CN)4] (v) [PtCl2(en)2](NO3)2 (iii) [Cr(en)3]Cl3 (vi) Fe4[Fe(CN)6]3 5.2 (i) Hexaamminecobalt(III) chloride (ii) Pentaamminechloridocobalt(III) chloride (iii) Potassium hexacyanidoferrate(III) (iv) Potassium trioxalatoferrate(III) (v) Potassium tetrachloridopalladate(II) (vi) Diamminechlorido(methanamine)platinum(II) chloride 5.3 (i) Both geometrical (cis-, trans-) and optical isomers for cis can exist. (ii) Two optical isomers can exist. (iii) There are 10 possible isomers. (Hint: There are geometrical, ionisation and linkage isomers possible). (iv) Geometrical (cis-, trans-) isomers can exist. 5.4 The ionisation isomers dissolve in water to yield different ions and thus react differently to various reagents: [Co(NH3)5Br]SO4 + Ba2+ ® BaSO4 (s) [Co(NH3)5SO4]Br + Ba2+ ® No reaction [Co(NH3)5Br]SO4 + Ag+ ® No reaction [Co(NH3)5SO4]Br + Ag+ ® AgBr (s) 5.6 In Ni(CO)4, Ni is in zero oxidation state whereas in NiCl42–, it is in +2 oxidation state. In the presence of CO ligand, the unpaired d electrons of Ni pair up but Cl– being a weak ligand is unable to pair up the unpaired electrons. 5.7 In presence of CN–, (a strong ligand) the 3d electrons pair up leaving only one unpaired electron. The hybridisation is d 2sp 3 forming inner orbital complex. In the presence of H2O, (a weak ligand), 3d electrons do not pair up. The hybridisation is sp 3d 2 forming an outer orbital complex containing five unpaired electrons, it is strongly paramagnetic. 5.8 In the presence of NH3, the 3d electrons pair up leaving two d orbitals empty to be involved in d2sp3 hybridisation forming inner orbital complex in case of [Co(NH3)6]3+. In Ni(NH3)6 2+, Ni is in +2 oxidation state and has d 8 configuration, the hybridisation involved is sp 3d 2 forming outer orbital complex. 5.9 For square planar shape, the hybridisation is dsp 2. Hence the unpaired electrons in 5d orbital pair up to make one d orbital empty for dsp2 hybridisation. Thus there is no unpaired electron. Chemistry 140 Reprint 2025-26

📋 Question Details

Chapter
Qualitative Analysis
Topic
Identification of inorganic sulphides
Year
2025
Shift
28 Jan Shift 2
Q Number
Q68
Type
MCQ
NCERT Ref
Class 11 Chemistry Ch 11: p-block Elements

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(1) 73 (2) 65 (3) 68 (4) 74 Q193.The equation of a circle with origin as a centre and passing through equilateral triangle whose median is of length 3a is JEE Main 2002 JEE Main Previous Year Paper (1) x2 + y2 = 9a2 (2) x2 + y2 = 16a2 (3) x2 + y2 = 4a2 (4) x2 + y2 = a2 Q194.In a triangle with sides a, b, c, r1 > r2 > r3 (which are the ex-radii) then (1) a > b > c (2) a < b < c (3) a > b and b < c (4) a < b and b > c Q195. log l p 1 l, m, n are the pth , qth and rth term of a G.P. all positive, then log m q 1 equals log n r 1 (1) -1 (2) 2 (3) 1 (4) 0 Q196. a b ax + b If a > 0 discriminant of ax2 + 2bx + c is -ve, then b c bx + c is ax + b bx + c 0 (1) +ve (2) (ac −b2) (ax2 + 2bx + c) (3) -ve (4) 0 Q197. cot−1(√cos α) = tan−1(√cos α) = x, then sin x = (1) tan2 ( α2 ) (2) cot2 ( α2 ) (3) tan α (4) cot ( α2 ) Q198.The domain of sin−1 [log3(x/3)] is (1) [1, 9] (2) [-1,9] (3) [-9, 1] (4) [-9, -1] Q199.Which one is not periodic (1) |sin 3x| + sin2 x (2) cos √x + cos2 x (3) cos 4x + tan2 x (4) cos 2x + sin x Q200.If f(x + y) = f(x) ⋅f(y)∀x ⋅y and f(5) = 2, f ′(0) = 3 then f ′(5) is (1) 0 (2) 1 (3) 6 (4) 2 Q201.f is defined in [-5, 5] as f(x) = x if x is rational and = -x is irrational. Then (1) f(x) is continuous at every x, except x = 0 (2) f(x) is discontinuous at every x, except x = 0 (3) f(x) is continuous everywhere (4) f(x) is discontinuous everywhere n d2y dy (1 + x2) dx2 + x dx is Q202.If y = (x + √1 + x2) , then (1) n2y (2) −n2y (3) −y (4) 2x2y Q203.The maximum distance from origin of a point on the curve x = a sin t −b sin ( atb ) y = a cos t −b cos ( atb ), both a, b > 0 is (1) a - b (2) a + b (3) √a2 + b2 (4) √a2 −b2 JEE Main 2002 JEE Main Previous Year Paper Q204. ∫10π0 | sin x|dx is (1) 20 (2) 8 (3) 10 (4) 18 xdx then Limn→∞n [In + In−2] equals Q205. In = ∫π/40 tann (1) 1/2 (2) 1 (3) ∞ (4) zero is Q206. ∫ 0√2 [x2]dx (1) 2 −√2 (2) 2 + √2 (3) √2 −1 (4) √2 −2 Q207. ∫π−π 2x(1+sin1+cos2 xx) dx is (1) π2 (2) π2 4 (3) zero (4) π 2 Q208.If y = f(x) makes +ve intercept of 2 and 0 unit on x and y axes and encloses an area of 3/4 square unit with the axes then ∫20 xf ′(x)dx is (1) 3/2 (2) 1 (3) 5/4 (4) -3/4 Q209.The area bounded by the curves y = ln x, y = ln |x|, y = | ln x| and y = | ln ||x| is (1) 4 sq. units (2) 6 sq. units (3) 10 sq. units (4) none of these d3y Q210.The order and degree of the differential equation 2/3 are + 3 dx = 4 dx3 (1 dy ) (1) (1, 32 ) (2) (3, 1) (3) (3, 3) (4) (1, 2) Q211.The solution of the equation d2y = e−2x dx2 (1) e−2x (2) e−2x 4 4 + cx + d (3) 4 1 e−2x + cx2 + d (4) 14 e−4x + cx + d Q212. f(x) and g(x) are two differentiable functions on [0, 2] such that f ′′(x) −g′′(x) = 0 f ′(1) = 2g′(1) = 4f(2) = 3g(2) = 9 then f(x) −g(x) at x = 3/2 is (1) 0 (2) 2 (3) 10 (4) 5 Q213.If |→a| = 4, |→b| = 2 and the angle between →a and →b is π/6 then (→a × →b)2 = 2 is equal to (1) 48 (2) 16 (3) →a (4) none of these Q214. If →a,→b, →c are vectors such that |→a→b→c| = 4 then (1) 16 (2) 64 (3) 4 (4) 8 JEE Main 2002 JEE Main Previous Year Paper Q215.If →a,→b, →c are vectors such that →a + →b + →c = 0 and |→a| = 7, |→b| = 5, |→c| = 3 then angle between vector →b and →c is (1) 60∘ (2) 30∘ (3) 45∘ (4) 90∘ Q216.If |a| = 5, |b| = 4, |c| = 3 thus what will be the value of |a ⋅b + b. c + c. a| , given that →a + →b + →c = 0 (1) 25 (2) 50 (3) -25 (4) -50 Q217. 3λ→c + 2μ(→a × →b) = 0 then (1) 3λ + 2μ = 0 (2) 3λ = 2μ (3) λ = μ (4) λ + μ = 0 Q218. →a = 3^i −5^j and →b = 6^i + 3^j are two vectors and →c is a vector such that →c = →a × →b then |→a| : |→b| : |→c| (1) √34 : √45 : √39 (2) √34 : √45 : 39 (3) 34 : 39 : 45 (4) 39 : 35 : 34 Q219.If →a × →b = →b × →c = →c × →a then →a + →b + →c = (1) abc (2) -1 (3) 0 (4) 2 Q220.The sum of two forces is 18 N and resultant whose direction is at right angles to the smaller force is 12 N. The magnitude of the two forces are (1) 13, 5 (2) 12, 6 (3) 14, 4 (4) 11, 7 Q221.A plane which passes through the point (3, 2, 0) and the line x−41 = y−75 = z−44 is (1) x - y + z = 1 (2) x + y + z = 5 (3) x + 2y - z = 1 (4) 2x - y + z = 5 Q222.The d.r. of normal to the plane through (1, 0, 0), (0, 1, 0) which makes an angle π/4 with plane x + y = 3 are (1) 1, √2, 1 (2) 1, 1, √2 (3) 1, 1, 2 (4) √2, 1, 1 Q223.A problem in mathematics is given to three students A, B, C and their respective probability of solving the problem is 2 1 , 13 and 14 . Probability that the problem is solved is (1) 3 (2) 1 4 2 (3) 2 (4) 1 3 3 Q224. A and B are events such that P(A ∪B) = 3/4, P(A ∩B) = 1/4, P(¯A) = 2/3 then P(¯A ∩B) is (1) 5/12 (2) 3/8 (3) 5/8 (4) 1/4 Q225.A die is tossed 5 times. Getting an odd number is considered a success. Then the variance of distribution of success is JEE Main 2002 JEE Main Previous Year Paper (1) 8/3 (2) 3/8 (3) 4/5 (4) 5/4 JEE Main 2002 JEE Main Previous Year Paper

2002
Hard

Q40.The correct order of increasing basicity of the given conjugate bases (R = CH3) is –––––– (1) RCOO < HC = C < R < NH2 (2) R < HC ≡C < RCOO < NH2 ––––– (3) RCOO < NH2 < HC ≡C < R (4) RCOO < HC ≡C < NH2 < R

2010
Medium

Q43.Copper wire test for halogens is known as (1) Duma's Test (2) Beilstein's Test (3) Liebig's Test (4) Lassigne's Test

2012
Easy

Q45.Beilstein test is used for the estimation of which one of the following elements? (1) S (2) Cl (3) C and H (4) N

2012
Easy
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