Q71.Equation of a common tangent to the circle, ๐ฅ2 + ๐ฆ2 - 6๐ฅ= 0 and the parabola, ๐ฆ2 = 4๐ฅ is: (1) 2โ3๐ฆ= - ๐ฅ- 12 (2) โ3๐ฆ= ๐ฅ+ 3 (3) โ3๐ฆ= 3๐ฅ+ 1 (4) 2โ3๐ฆ= 12๐ฅ+ 1
What This Question Tests
This question tests the ability to find a common tangent by formulating the tangent equation for one conic (parabola) and then applying the tangency condition (distance from center equals radius) for the other conic (circle).
Concepts Tested
Formulas Used
Tangent to yยฒ=4ax is y=mx+a/m
Distance from center to tangent = radius for circle
๐ NCERT Sections This Tests
2.1 โ Two Charges 5 ร 10โ8 C And โ3 ร 10โ8 C Are Located 16 Cm Apart. At
Physics Class 11 ยท Chapter 2
2.1 Two charges 5 ร 10โ8 C and โ3 ร 10โ8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
6.11 โ Dynamics Of Rotational
Physics Class 11 ยท Chapter 6
6.11 Dynamics of rotational the motion of extended bodies. motion about a fixed axis A large class of problems with extended bodies can be
9.15 โ Apply Mirror Equation And The Condition:
Physics Class 12 ยท Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
๐ Question Details
- Chapter
- Parabola
- Topic
- Common tangents to circle and parabola
- Year
- 2019
- Shift
- 09 Jan Shift 1
- Q Number
- Q71
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 11: Conic Sections
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