Q26.In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300nm to 400nm. The decrease in the stopping potential is close to : ( hce = 1240nm −V) (1) 0.5 V (2) 1.5 V (3) 1.0 V (4) 2.0 V JEE Main 2019 (11 Jan Shift 2) JEE Main Previous Year Paper
What This Question Tests
This question tests the application of Einstein's photoelectric equation to calculate the change in stopping potential when the wavelength of incident light is changed.
Concepts Tested
Formulas Used
eV_s = hc/λ - Φ
hc/e = 1240 nm-V
📚 NCERT Sections This Tests
11.5 — In An Experiment On Photoelectric Effect, The Slope Of The Cut-Off Voltage
Physics Class 12 · Chapter 11
11.5 In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10–15 V s. Calculate the value of Planck’s constant.
11.3 — The Photoelectric Cut-Off Voltage In A Certain Experiment Is 1.5 V.
Physics Class 12 · Chapter 11
11.3 The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?
11.9 — Light Of Wavelength 488 Nm Is Produced By An Argon Laser Which Is
Physics Class 12 · Chapter 11
11.9 Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.
📋 Question Details
- Chapter
- Dual Nature of Matter
- Topic
- Photoelectric effect
- Year
- 2019
- Shift
- 11 Jan Shift 2
- Q Number
- Q26
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 11: Dual Nature of Radiation and Matter
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