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PhysicsMediumMCQ2012 · 07 May Online

Q17.The electric potential V (x) in a region around the origin is given by V (x) = 4x2 volts. The electric charge enclosed in a cube of 1 m side with its centre at the origin is (in coulomb) (1) 8ε0 (2) −4ε0 (3) 0 (4) −8ε0 JEE Main 2012 (07 May Online) JEE Main Previous Year Paper

What This Question Tests

The question requires deriving the electric field from the potential and then using Gauss's law in differential form to determine the charge density and subsequently the enclosed charge.

Concepts Tested

Relationship between electric potential and electric fieldGauss's Law in differential formCharge density

Formulas Used

E = -∇V

∇⋅E = ρ/ε₀

Q_enc = ∫ρ dV

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