Q65.If the fourth term in the Binomial expansion of ( x2 + xlog8x)6, (x > 0) is 20 × 87, then a value of (1) 8–2 (2) 8 (3) 83 (4) 82
What This Question Tests
This question applies the general term formula of the binomial expansion. After setting the fourth term equal to the given value, the resulting equation involves 'x' and logarithms, requiring algebraic and logarithmic manipulation to solve for 'x'.
Concepts Tested
Formulas Used
Tr+1 = nCr * a^(n-r) * b^r
log(x^y) = y*log(x)
📚 NCERT Sections This Tests
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
3.16 — The Rate Constant For A First Order Reaction Is 60 S–1. How Much Time Will
Chemistry Class 11 · Chapter 3
3.16 The rate constant for a first order reaction is 60 s–1. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value?
📋 Question Details
- Chapter
- Binomial Theorem
- Topic
- General term of binomial expansion
- Year
- 2019
- Shift
- 09 Apr Shift 1
- Q Number
- Q65
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 8: Binomial Theorem
More from this Chapter
Q89.In the binomial expansion of (a −b)n, n ≥5 , the sum of 5th and 6th terms is zero, then ab equals (1) 5 (2) 6 n−4 n−5 (3) n−5 (4) n−4 6 5
Q90.The sum of the series 20C0 −20C1 + 20C2 −20C3 + … −… + 20C10 is (1) −20C10 (2) 12 20C10 (3) 0 (4) 20C10
Q77.Statement-1: ∑nr=0(r + 1)nCr = (n + 2)2n−1 Statement -2: ∑nr=0(r + 1)nCrxr = (1 + x)n + nx(1 + x)n−1 . JEE Main 2008 JEE Main Previous Year Paper (1) Statement −1 is false, Statement −2 is true (2) Statement −1 is true, Statement −2 is true, Statement −2 is a correct explanation for Statement −1 (3) Statement −1 is true, Statement −2 is true; (4) Statement −1 is true, Statement −2 is false. Statement −2 is not a correct explanation for Statement −1.
Q65.The remainder left out when 82n −(62)2n+1 is divided by 9 is (1) 0 (2) 2 (3) 7 (4) 8