Q41.For the coagulation of a negative sol, the species below, that has the highest flocculating power is: (1) SO2−4 (2) Ba2+ (3) Na+ (4) PO3−4
What This Question Tests
This question tests the understanding of the Hardy-Schulze rule for the coagulation of colloids, specifically that for a negative sol, the flocculating power of a cation increases with its charge.
Concepts Tested
📚 NCERT Sections This Tests
1.23 — Suggest The Most Important Type Of Intermolecular Attractive Interaction In
Chemistry Class 11 · Chapter 1
1.23 Suggest the most important type of intermolecular attractive interaction in the following pairs. (i) n-hexane and n-octane (ii) I2 and CCl4 (iii) NaClO4 and water (iv) methanol and acetone (v) acetonitrile (CH3CN) and acetone (C3H6O). 1.24 Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, CH3OH, CH3CN.
5.17 — What Is Spectrochemical Series? Explain The Difference Between A Weak
Chemistry Class 11 · Chapter 5
5.17 What is spectrochemical series? Explain the difference between a weak field ligand and a strong field ligand.
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
📋 Question Details
- Chapter
- Surface Chemistry
- Topic
- Coagulation and Flocculation
- Year
- 2021
- Shift
- 17 Mar Shift 2
- Q Number
- Q41
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 5: Surface Chemistry
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