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PhysicsMediumMCQ2012 · 19 May Online

Q19.A proton and a deuteron are both accelerated through the same potential difference and enter in a magnetic field perpendicular to the direction of the field. If the deuteron follows a path of radius R, assuming the neutron and proton masses are nearly equal, the radius of the proton's path will be (1) √2R (2) R √2 (3) R (4) R 2

What This Question Tests

This question requires combining the concepts of kinetic energy gained by a charged particle in an electric field and the radius of its path in a perpendicular magnetic field.

Concepts Tested

Kinetic energy from potential differenceRadius of circular path in magnetic fieldLorentz force

Formulas Used

KE = qV

KE = ½mv²

r = mv/qB

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