Q88.Let π¦= π¦π₯ be the solution of the differential equation sec2π₯ππ₯+ π2π¦tan2π₯+ tanπ₯ππ¦= 0, 0 < π₯< π π¦π = 0. 2, 4 π If π¦ = πΌ, then π8πΌ is equal to ______. 6
What This Question Tests
This question tests the application of definite integral properties, particularly the King's property (a to b integral of f(x) is equal to a to b integral of f(a+b-x)), along with trigonometric identities to simplify the integrand.
Concepts Tested
Formulas Used
β«βα΅ f(x) dx = β«βα΅ f(a-x) dx
sin^2(x) + cos^2(x) = 1
sin(2x) = 2sin(x)cos(x)
π NCERT Sections This Tests
2.1 β Two Charges 5 Γ 10β8 C And β3 Γ 10β8 C Are Located 16 Cm Apart. At
Physics Class 11 Β· Chapter 2
2.1 Two charges 5 Γ 10β8 C and β3 Γ 10β8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
8.17 β Complete Each Synthesis By Giving Missing Starting Material, Reagent Or Products
Chemistry Class 12 Β· Chapter 8
8.17 Complete each synthesis by giving missing starting material, reagent or products
2.2 β A Regular Hexagon Of Side 10 Cm Has A Charge 5 Mc At Each Of Its
Physics Class 11 Β· Chapter 2
2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.
π Question Details
- Chapter
- Definite Integration & Area
- Topic
- Properties of definite integrals
- Year
- 2024
- Shift
- 31 Jan Shift 2
- Q Number
- Q88
- Type
- Numerical
- NCERT Ref
- Class 12 Mathematics Ch 7: Integrals
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