Q17.A wire of resistance 160 Ω is melted and drawn in a wire of one-fourth of its length. The new resistance of the wire will be (1) 16 Ω (2) 10 Ω (3) 640 Ω (4) 40 Ω
What This Question Tests
This question tests the understanding of Gauss's Law and the fundamental property of an electric dipole having zero net charge, leading to zero net flux through a closed surface.
Concepts Tested
Formulas Used
Φ_E = Q_enclosed / ε_0
📚 NCERT Sections This Tests
1.18 — A Point Charge Of 2.0 Mc Is At The Centre Of A Cubic Gaussian
Physics Class 11 · Chapter 1
1.18 A point charge of 2.0 mC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?
1.19 — A Point Charge Causes An Electric Flux Of –1.0 × 103 Nm2/C To Pass
Physics Class 11 · Chapter 1
1.19 A point charge causes an electric flux of –1.0 × 103 Nm2/C to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. (a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface? (b) What is the value of the point charge?
2.4 — A Spherical Conductor Of Radius 12 Cm Has A Charge Of 1.6 × 10–7C
Physics Class 11 · Chapter 2
2.4 A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field (a) inside the sphere (b) just outside the sphere (c) at a point 18 cm from the centre of the sphere?
📋 Question Details
- Chapter
- Electrostatics
- Topic
- Gauss's Law, Electric Dipole
- Year
- 2023
- Shift
- 12 Apr Shift 1
- Q Number
- Q17
- Type
- Assertion Reasoning
- NCERT Ref
- Class 12 Physics Ch 1: Electric Charges and Fields
More from this Chapter
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